By Hei-Chi Chan

ISBN-10: 9814343846

ISBN-13: 9789814343848

The purpose of those lecture notes is to supply a self-contained exposition of a number of attention-grabbing formulation came upon by way of Srinivasa Ramanujan. critical ends up in those notes are: (1) the review of the Rogers-Ramanujan persisted fraction -- a consequence that confident G H Hardy that Ramanujan used to be a "mathematician of the top class", and (2) what G. H. Hardy known as Ramanujan's "Most appealing Identity". This ebook covers quite a number similar effects, comparable to a number of proofs of the well-known Rogers-Ramanujan identities and an in depth account of Ramanujan's congruences. It additionally covers a variety of strategies in q-series.

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**Additional info for An Invitation to Q-Series: From Jacobi's Triple Product Identity to Ramanujan's "Most Beautiful Identity"**

**Example text**

Next we use Eqs. 4) for subtraction. For example, the diﬀerence of the third terms gives 7 8 7 5 8 5 q = q , q − 3 2 3 where we have used Eq. 4) to expand 8 . After all these are done, we 3 have D10 − D9 − q 8 D8 = 7 9 7 9 7 5 7 5 q − q + q − q = 0, 7 7 2 2 with the desired cancelations clearly displayed. 4 Question (2)). Below we will follow an approach that allows us to verify Eq. 2) without considering separately the case of n being even and the case of n being odd. -C. -C. Chan and Ebbing (2008).

2. e, the maximal abelian subalgebra of g acting diagonally). (2) In the present case, we have dim h = 1. In general, the dimension of the Cartan subalgebra is called the rank of the Lie algebra. The decomposition in Eq. 7) can be viewed as the decomposition of g under the adjoint action of h. This is where the concept of roots enters. Precisely, α is called a root of g if α ∈ h∗ = Hom(h, C) = the dual of h such that [h, eα ] = α(h) eα . That is, the pairing α(h) gives the eigenvalue of h (under the adjoint action [h, • ]) with eigenvector eα .

Let us deﬁne (with n ∈ Z) vac(n):= the state with all levels < n being occupied. Note that vac = vac(0). Any admissible state S with charge n can be constructed as follows. • Start with the state vac(n). • Move the top occupied level (i = n − 1/2) to n − 1/2 + λ1 , the top occupied level in the desired state S. • Move the next occupied level (i = n − 3/2) to n − 3/2 + λ2 . Note that n − 1/2 + λ1 > n − 3/2 + λ2 (the occupancy of each level is almost 1) implies λ1 ≥ λ2 . • Keep repeating this procedure until the desired state is obtained.

### An Invitation to Q-Series: From Jacobi's Triple Product Identity to Ramanujan's "Most Beautiful Identity" by Hei-Chi Chan

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